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In topology we defined the notion of a topological manifold; in this series we study differentiable manifolds, and in particular smooth manifolds.

Notation

We will frequently deal with \(m\)-dimensional coordinate systems, so we fix the following notation. For \(\mathbb{R}^m\), we denote the \(i\)-th projection \(\pr_i\) by \(r^i\). Similarly, for any set \(X\) and function \(f:X\rightarrow\mathbb{R}^m\), the \(i\)-th component function of \(f\) is defined by the formula \(f^i=r^i\circ f\).

Now let \(f\) be a function from \(\mathbb{R}^m\) to \(\mathbb{R}\). Then we define the partial derivative of \(f\) with respect to the \(i\)-th coordinate by the formula

\[\frac{\partial}{\partial r^i}\bigg|_t f=\frac{\partial f}{\partial r^i}\bigg|_t=\lim_{h\rightarrow 0}\frac{f(t^1,\ldots, t^{i-1}, t^i+h, t^{i+1},\ldots, t^m)-f(t^1,\ldots, t^m)}{h}\]

As in the notation above, following [Lee] we write the \(i\)-th coordinate as \(x^i\) rather than \(x_i\).

If all the component functions are \(k\) times differentiable and the resulting derivatives are continuous, we call \(f\) a \(C^k\) function. For example, saying that a function \(f:\mathbb{R}^2\rightarrow\mathbb{R}\) is \(C^2\) means that the following partial derivatives

\[\frac{\partial^2 f}{\partial x^2},\quad\frac{\partial^2 f}{\partial x\partial y},\quad\frac{\partial^2 f}{\partial y\partial x},\quad\frac{\partial^2 f}{\partial y^2}\]

all exist and are continuous. If \(f\) is \(C^k\) for every natural number \(k\), we call it \(C^\infty\).

Differentiable Manifolds

Unlike a general topological space, a topological manifold looks locally like \(\mathbb{R}^n\), so we can carry over the notion of differentiation defined there to \(M\). The reason this is possible is that differentiability is essentially a local property.

Definition 1 Let a topological manifold \(M\) be given. For \(0\leq k\leq\infty\), we say that coordinate charts \((U,\varphi)\) and \((V,\psi)\) are \(C^k\)-compatible if the two transition maps

\[\psi\circ\varphi^{-1}:\varphi(U\cap V)\rightarrow\psi(U\cap V),\qquad\varphi\circ\psi^{-1}:\psi(U\cap V)\rightarrow\varphi(U\cap V)\]

are both \(C^k\). A collection \(\mathcal{A}=\{(U_\lambda, \varphi_\lambda)\}_{\lambda\in\Lambda}\) of \(C^k\)-compatible charts satisfying \(M=\bigcup U_\lambda\) is called a \(C^k\)-atlas.

Among the \(C^k\)-atlases defined on \(M\), one that is maximal with respect to inclusion is called a \(C^k\)-differentiable structure, and in this case \(M\) is called a \(C^k\)-differentiable manifold. In the special case \(k=\infty\), this structure is called a smooth differentiable manifold, or more simply a differentiable manifold.

The reason we think of a maximal atlas as giving a differentiable structure is that it is quite possible for two non-maximal atlases to define essentially the same differentiable structure. For example, \(\mathbb{R}\) admits the following \(C^\infty\)-atlas

\[\mathcal{A}=\{(\mathbb{R}, \id_\mathbb{R})\}\]

but also another atlas

\[\mathcal{A}'=\{((-\infty, 1), \id_{(-\infty, 1)}), ((-1, \infty),\id_{(-1,\infty)})\}\]

However, as we shall verify in Proposition 3, given any atlas there is a uniquely determined maximal atlas containing it, so in an essential sense this is not a serious difference.

Meanwhile, to understand an object in mathematics it suffices to understand the functions defined on it. Henceforth, all manifolds are understood to be smooth differentiable manifolds.

Definition 2 Consider a manifold \(M\) and a point \(p\in M\). A function \(f\) defined on some open neighborhood of \(p\) is said to be \(C^\infty\) at \(p\) if there exists a coordinate chart \((U,\varphi)\) containing \(p\) such that the function \(f\circ\varphi^{-1}:U'\rightarrow\mathbb{R}\) is \(C^\infty\) at the point \(\varphi(p)\).

Suppose another coordinate chart \((V,\psi)\) is defined on another open neighborhood of \(p\). If \(f\circ\varphi^{-1}\) were \(C^\infty\) at \(\varphi(p)\) but \(f\circ\psi^{-1}\) were not \(C^\infty\) at \(\psi(p)\), this definition would be ill-defined. However, on \(\psi(U\cap V)\) we have

\[f\circ\psi^{-1}=(f\circ\varphi^{-1})\circ(\varphi\circ\psi^{-1})\]

and therefore \(f\circ\psi^{-1}\) is \(C^\infty\) at \(\psi(p)\). By a similar argument one can prove the following.

Proposition 3 Let a \(C^k\)-atlas \(\mathcal{A}\) be given on a topological manifold \(M\). Then there exists a unique maximal \(C^k\)-atlas containing \(\mathcal{A}\). Hence any \(C^k\)-atlas \(\mathcal{A}\) defines a unique \(C^k\)-differentiable structure on \(M\).

Proof

Define \(\mathcal{A}'\) by the formula

\[\mathcal{A}'=\{(V,\psi)\mid\psi\circ\varphi_\lambda^{-1}, \varphi_\lambda\circ\psi^{-1}\text{ are $C^k$ for all $\varphi_\lambda\in\mathcal{A}$}\}\]

Then \(\mathcal{A}'\) contains \(\mathcal{A}\), and therefore covers \(M\) by coordinate charts. Moreover, if \((V,\psi)\) and \((V',\psi')\) are elements of \(\mathcal{A}'\) and \(V\cap V'\neq\emptyset\), then the transition map

\[\psi'\circ\psi^{-1}:\psi(V\cap V')\rightarrow\psi'(V\cap V')\]

is \(C^k\). For any \(p\in\psi(V\cap V')\), pick \((U,\varphi)\in\mathcal{A}\) with \(p\in U\); then on \(U\cap V\cap V'\) we have

\[\psi'\circ\psi^{-1}=(\psi'\circ\varphi^{-1})\circ(\varphi\circ\psi^{-1})\]

so that \(\psi'\circ\psi^{-1}\) is \(C^k\) at the point \(p\). Since \(p\) was chosen arbitrarily, this shows that \(\psi'\circ\psi^{-1}\) is \(C^k\). Of course, by interchanging the roles of \((V,\psi)\) and \((V',\psi')\) one can show that the transition map in the opposite direction is also \(C^k\).

Obviously \(\mathcal{A}'\) is a maximal \(C^k\)-atlas by definition, and its uniqueness is easily verified.

Example 4 Consider two atlases on the set of real numbers \(\mathbb{R}\):

\[\mathcal{A}_1=\{(\mathbb{R},\id_\mathbb{R})\},\qquad \mathcal{A}_2=\{(\mathbb{R}, x\mapsto x^3)\}\]

Since these consist of a single chart, they are obviously \(C^\infty\). By the preceding Proposition 3, there exists a differentiable structure containing each of them. But they are not equal. This is because the two charts \((\mathbb{R},\id_\mathbb{R})\) and \((\mathbb{R}, x\mapsto x^3)\) are not \(C^\infty\)-compatible. (\(x\mapsto x^3\) is a \(C^\infty\) function, but its inverse \(x\mapsto x^{1/3}\) is not.)

Nevertheless, although the two atlases in Example 4 do not give the same differentiable structure, they give diffeomorphic differentiable structures.

Smooth partition of unity

We showed that a continuous partition of unity exists on any topological manifold; however, when dealing with differentiable manifolds a merely continuous partition of unity is of little use. For example, if we multiply an arbitrary \(C^\infty\) function by a partition of unity that is merely continuous, the differentiability of the function is immediately weakened.

Therefore we need to construct a smooth partition of unity, and for this it suffices to prove the following lemma.

Lemma 5 (\(C^\infty\) Urysohn lemma) Let real numbers \(a'<a<b<b'\) be given. Then there exists a \(C^\infty\) function \(\psi:\mathbb{R}\rightarrow[0,1]\) that is equal to \(1\) on \([a,b]\) and equal to \(0\) outside \((a',b')\).

Proof

We may assume without loss of generality that \(a'=-2\), \(a=-1\), \(b=1\), and \(b'=2\). First define a function \(f\) by

\[f(t)=\begin{cases}e^{-1/t}&t>0\\0&t\leq 0\end{cases}\]

In particular, \(f\) is always non-negative and is \(C^\infty\). Now define

\[g(t)=\frac{f(t)}{f(t)+f(1-t)}\]

Then \(g\) is likewise always non-negative, its values are always at most \(1\), and in particular \(g(t)\equiv 1\) for \(t\geq 1\) and \(g(t)\equiv 0\) for \(t\leq 0\). Therefore, defining \(\psi\) by the formula

\[\psi(t)=g(t+2)g(2-t)\]

gives the desired function.

Using the above \(C^\infty\) Urysohn lemma instead of the ordinary Urysohn lemma, one can construct a smooth partition of unity on a differentiable manifold.


References

[Lee] John M. Lee. Introduction to Smooth Manifolds, Graduate texts in mathematics, Springer, 2012
[War] Frank W. Warner. Foundations of Differentiable Manifolds and Lie Groups, Graduate texts in mathematics, Springer, 2013


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